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一元一次方程式… 急急急

Dec 31st 2013, 10:57

將77分成四個數，如果第一個數加14，第二數減3，第三個數乘2，第四個數
除以3，所得的數相同，則此四個數為?
Sol
設四個數分別為a，b，c，d
a+b+c+d=77
a+14=b－3=c*2=d/3=p
(p－14)+(p+3)+(p/2)+(3p)=77
(2p－28)+(2p+6)+p+6p=154
11p－22=154
11p=176
p=16
a=2，b=19，c=8，d=48

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