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國二上自然求詳解

Sep 22nd 2013, 02:15

不同溫度，溶液的飽和濃度亦不相同
"或向其中加入20g KNO3固體，"
幫您修改為"或原温度向其中加入20g KNO3固體"

設原温度下的溶質有x公克KNO3固體，
同溫度，溶液的飽和濃度相同
x/(100-10) = (x+20)/(100+20)
x=60

飽和濃度w%= 60/(100-10) *100% = 66.67%

參考資料 me

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